A Rhombus is a special type of quadrilateral that plays an important role in Geometry, especially in competitive exams like RRB NTPC, Group D, and SSC.
A rhombus is a four-sided figure (quadrilateral) with all sides equal and diagonals that bisect each other at right angles (90°).
In Hindi:
समचतुर्भुज एक ऐसा चतुर्भुज होता है जिसकी सभी भुजाएँ बराबर होती हैं और विकर्ण एक-दूसरे को समद्विभाजित करते हैं तथा 90° पर काटते हैं।
Property | Explanation |
---|---|
All sides equal | AB = BC = CD = DA |
Opposite angles equal | ∠A = ∠C, ∠B = ∠D |
Diagonals intersect at 90° | AC ⊥ BD |
Diagonals bisect each other | Each diagonal cuts the other into two equal halves |
Diagonals bisect angles | Each diagonal divides vertex angles equally |
The area of a rhombus is given by the product of its diagonals divided by 2:
Where:
In Hindi:
Q. Diagonals of a rhombus are 10 cm and 8 cm. Find its area.
Solution:
✅ Answer: 40 cm²
Shape | Area Formula | Diagonal Property |
---|---|---|
Square | side² or 1/2 × d₁ × d₂ | Equal diagonals at 90° |
Rectangle | l × b | Equal diagonals |
Rhombus | 1/2 × d₁ × d₂ | Unequal diagonals at 90° |
Parallelogram | b × h | No specific diagonal rule |
(This is derived using the Pythagoras Theorem.)
D
/ \
d1/ \d1
/ \
A-------C
| |
d2 | | d2
| |
B-------B
Note: Diagonals AC and BD intersect at 90° and divide the rhombus into 4 right-angled triangles.
Try solving 3–5 rhombus-based questions to solidify your understanding.